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Introduction to Linear Algebra

Exercise 2.7.5

Answers

(a): We have $x^{T} A y = [\begin{matrix} 0 & 1 \end{matrix}] [\begin{matrix} 1 & 2 & 3 \\ 4 & 5 & 6 \end{matrix}] [\begin{matrix} 0 \\ 1 \\ 0 \end{matrix}] = 5 .$
(b): This is the row $x^{T} A = [\begin{matrix} 4 & 5 & 6 \end{matrix}]$ times $y$ .
(c): This is also the row $x^{T}$ times $A y = [\begin{matrix} 2 \\ 5 \end{matrix}] .$

mathchakra

2021-12-20 21:26

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