Exercise 3.2.13

Answers

Fill in 12 then 3 then 1 to get the complete solution in $R^{3}$ to $x - 3 y - z = 12$ :

[\begin{matrix} x \\ y \\ z \end{matrix}] = [\begin{matrix} 12 \\ 0 \\ 0 \end{matrix}] + y [\begin{matrix} 3 \\ 1 \\ 0 \end{matrix}] + z [\begin{matrix} 1 \\ 0 \\ 1 \end{matrix}] = one particular solution + all nullspace solutions.

mathchakra

2022-01-23 10:40