Exercise 3.2.15

Answers

To produce special solutions $(2, 2, 1, 0)$ and $(3, 1, 0, 1)$ with free variables $x_{3}, x_{4} :$

R = [\begin{matrix} 1 & 0 & - 2 & - 3 \\ 0 & 1 & - 2 & - 1 \end{matrix}]

and $A$ can be any invertible 2 by 2 matrix times this $R$ .

mathchakra

2022-01-23 10:40