Exercise 3.2.41

Answers

We have

[\begin{matrix} 3 & 6 & 6 \\ 1 & 2 & 2 \\ 4 & 8 & 8 \end{matrix}] = [\begin{matrix} 3 \\ 1 \\ 4 \end{matrix}] [\begin{matrix} 1 & 2 & 2 \end{matrix}]

and

[\begin{matrix} 2 & 2 & 6 & 4 \\ - 1 & - 1 & - 3 & - 2 \end{matrix}] = [\begin{matrix} 2 \\ - 1 \end{matrix}] [\begin{matrix} 1 & 1 & 3 & 2 \end{matrix}] .

mathchakra

2022-01-23 13:57