Homepage › Solution manuals › Gilbert Strang › Introduction to Linear Algebra › Exercise 3.2.50

Exercise 3.2.50

Answers

We are given $AB = I$ which has rank $n .$ Then $rank (AB) \leq rank (A)$ forces $rank (A) =$ $n$ . This means that $A$ is invertible. The right-inverse $B$ is also a left-inverse: $BA = I$ and $B = A^{- 1}$

mathchakra

2022-01-23 14:02

Exercise 3.2.50

Answers

Comments

Add answer