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Introduction to Linear Algebra

Exercise 3.3.20

Answers

$A = LU = [\begin{matrix} 1 & 0 \\ 2 & 1 \end{matrix}] [\begin{matrix} 3 & 4 & 1 & 0 \\ 0 & - 3 & 0 & 1 \end{matrix}];$
$A = LU = [\begin{matrix} 1 & 0 & 0 \\ 2 & 1 & 0 \\ 0 & 3 & 1 \end{matrix}] [\begin{matrix} 1 & 0 & 1 & 0 \\ 0 & 2 & - 2 & 3 \\ 0 & 0 & 11 & - 5 \end{matrix}] .$

mathchakra

2022-01-23 15:02

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