Exercise 3.3.7

Answers

[\begin{matrix} 1 & 3 & 1 & b_{1} \\ 3 & 8 & 2 & b_{2} \\ 2 & 4 & 0 & b_{3} \end{matrix}] \to [\begin{matrix} 1 & 3 & 1 & b_{2} \\ 0 & - 1 & - 1 & b_{2} - 3 b_{1} \\ 0 & - 2 & - 2 & b_{3} - 2 b_{1} \end{matrix}] .

One more step gives $[\begin{matrix} 0 & 0 & 0 \end{matrix}] = row 3 - 2 (row 2) + 4 (row 1)$ .

mathchakra

2022-01-23 14:56