Exercise 3.3.9

Answers

L [U c] = [\begin{matrix} 1 & 0 & 0 \\ 2 & 1 & 0 \\ 3 & - 1 & 1 \end{matrix}] [\begin{matrix} 1 & 2 & 3 & 5 & b_{1} \\ 0 & 0 & 2 & 2 & b_{2} - 2 b_{1} \\ 0 & 0 & 0 & 0 & b_{3} + b_{2} - 5 b_{1} \end{matrix}] = [\begin{matrix} 1 & 2 & 3 & 5 & b_{1} \\ 2 & 4 & 8 & 12 & b_{2} \\ 3 & 6 & 7 & 13 & b_{3} \end{matrix}] = [A b];

Particular $x_{p} = (- 9, 0, 3, 0)$ means $- 9 (1, 2, 3) + 3 (3, 8, 7) = (0, 6, - 6) .$ This is $A x_{p} = b$ .

mathchakra

2022-01-23 14:57