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Exercise 3.4.36

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Basis for $S : (1, 0, - 1, 0), (0, 1, 0, 0), (1, 0, 0, - 1);$ basis for $T : (1, - 1, 0, 0)$ and $(0, 0, 2, 1);$ $S \cap T =$ multiples of $(3, - 3, 2, 1) =$ nullspace for 3 equations in $R^{4}$ has dimension $1 .$

mathchakra

2022-01-23 15:58

Exercise 3.4.36

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