Exercise 4.1.5

Answers

(a) If A x = b has a solution and A T y = 0 , then y is perpendicular to b . b T y = ( A x ) T y = x T ( A T y ) = 0 . This says again that C ( A ) is orthogonal to N ( A T ) . (b) If A T y = ( 1 , 1 , 1 ) has a solution, ( 1 , 1 , 1 ) is a combination of the rows of A . It is in the row space and is orthogonal to every x in the nullspace.

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2023-09-08 14:57
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