Homepage › Solution manuals › Gilbert Strang › Introduction to Linear Algebra › Exercise 4.2.1
(a) a T b ∕ a T a = 5 ∕ 3 ; p = 5 a ∕ 3 = ( 5 ∕ 3 , 5 ∕ 3 , 5 ∕ 3 ) ; e = ( − 2 , 1 , 1 ) ∕ 3
(b) a T b ∕ a T a = − 1 ; p = − a ; e = 0 .
