Exercise 4.2.22

Answers

P^{T} = {(A {(A^{T} A)}^{- 1} A^{T})}^{T} = A {({(A^{T} A)}^{- 1})}^{T} A^{T} = A {(A^{T} A)}^{- 1} A^{T} = P .

$A^{T} A$ is symmetric!

mathchakra

2023-09-14 07:38