Exercise 4.3.4

Answers

E = ( C + 0 D ) 2 + ( C + 1 D − 8 ) 2 + ( C + 3 D − 8 ) 2 + ( C + 4 D − 20 ) 2 .

Then

∂E ∕ ∂C = 2 C + 2 ( C + D − 8 ) + 2 ( C + 3 D − 8 ) + 2 ( C + 4 D − 20 ) = 0

and

∂E ∕ ∂D = 1 ⋅ 2 ( C + D − 8 ) + 3 ⋅ 2 ( C + 3 D − 8 ) + 4 ⋅ 2 ( C + 4 D − 20 ) = 0 .

These two normal equations are again

[ 4 8 8 26 ] [ C D ] = [ 36 112 ] .

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2023-09-14 08:04
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