Exercise 4.4.14

Answers

[\begin{matrix} 1 & 4 \\ 1 & 0 \end{matrix}] = [\begin{matrix} q_{1} & q_{2} \end{matrix}] [\begin{matrix} ∥ a ∥ & q_{1}^{T} b \\ 0 & ∥ B ∥ \end{matrix}] = [\begin{matrix} 1 ∕ \sqrt{2} & 1 ∕ \sqrt{2} \\ 1 ∕ \sqrt{2} & - 1 ∕ \sqrt{2} \end{matrix}] [\begin{matrix} \sqrt{2} & 2 \sqrt{2} \\ 0 & 2 \sqrt{2} \end{matrix}] = QR .

mathchakra

2023-09-14 08:26