Exercise 4.4.26

Answers

(q_{2}^{T} C^{∗}) q_{2} = \frac{B^{T} c}{B^{T} B} B

because $q_{2} = \frac{B}{∥ B ∥}$ and the extra $q_{1}$ in $C^{∗}$ is orthogonal to $q_{2}$ .

mathchakra

2023-09-14 08:31