Exercise 4.4.2

Answers

Divide by length 3 to get

q_{1} = (\begin{matrix} \frac{2}{3}, \frac{2}{3}, \frac{2}{- 3} \end{matrix}) .

We have

Q^{T} Q = [\begin{matrix} 1 & 0 \\ 0 & 1 \end{matrix}]

but

Q Q^{T} = [\begin{matrix} 5 ∕ 9 & 2 ∕ 9 & - 4 ∕ 9 \\ 2 ∕ 9 & 8 ∕ 9 & 2 ∕ 9 \\ - 4 ∕ 9 & 2 ∕ 9 & 5 ∕ 9 \end{matrix}] .

mathchakra

2023-09-14 08:39