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Exercise 1.10.3

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We have $x = M^{- \frac{1}{2}} y = [\begin{matrix} 1 & 0 \\ 0 & \frac{1}{2} \end{matrix}] y$ . It’s easy to see that the $x_{1}, x_{2}$ and $y_{1}, y_{2}$ above satisfy this condition.

niuers

2020-03-20 00:00

Exercise 1.10.3

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