Exercise 1.12.2

Answers

The error vector $a_{1} - v_{1} u$ is perpendicular to $u$ . We can find the number $v_{1}$ that minimizes $| | a_{1} - v_{1} u | |^{2}$ . That is:

$(a_1 - v_1u)^Tu = (a^T_1 - v_1 u^T)u = a^T_1u - v_1 u^Tu = 0 $ so we obtain the same formula as problem I.12.1.

niuers

2020-03-20 00:00