Exercise 1.3.9

Answers

A = [1 1 0 0 0 0 1 1 0 0 0 0 11 0 1 0 0 1 0 1 0 0 0 1 0 1 0 0 1 0 0 1 0 1 0 0 0 1 1 ]

One vector in N(A) is [1 1 1 1 1 ]

The four independent vectors in N(AT) are identified from the four loops in the graph:

v1 = [1 0 0 0 1 1 0 0 ] v2 = [ 0 1 0 0 0 1 1 0 ] v3 = [ 0 0 1 0 0 0 1 1 ] v4 = [ 0 0 0 1 1 0 0 1 ]

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2020-03-20 00:00
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