Exercise 1.4.1

Answers

A = [\begin{matrix} 2 & 1 \\ 6 & 7 \end{matrix}] = [\begin{matrix} 1 & 0 \\ 3 & 1 \end{matrix}] [\begin{matrix} 2 & 1 \\ 0 & 4 \end{matrix}]

A = [\begin{matrix} 1 & 1 & 1 \\ 1 & 1 & 1 \\ 1 & 1 & 1 \end{matrix}] = [\begin{matrix} 1 & 0 & 0 \\ 1 & 1 & 0 \\ 1 & 0 & 1 \end{matrix}] [\begin{matrix} 1 & 1 & 1 \\ 0 & 0 & 0 \\ 0 & 0 & 0 \end{matrix}]

A = [\begin{matrix} 2 & - 1 & 0 \\ - 1 & 2 & - 1 \\ 0 & - 1 & 2 \end{matrix}] = [\begin{matrix} 1 & 0 & 0 \\ - \frac{1}{2} & 1 & 0 \\ 0 & - \frac{2}{3} & 1 \end{matrix}] [\begin{matrix} 2 & - 1 & 0 \\ 0 & \frac{3}{2} & - 1 \\ 0 & 0 & \frac{4}{3} \end{matrix}]

niuers

2020-03-20 00:00