Exercise 1.5.1

Answers

If u and v are orthogonal unit vectors, then we have

(u+v)T(uv) = (uT+vT)(uv) = uTuuTv+vuTvTv = 1+001 = 0,

so u + v is orthogonal to u v.

Similarly,

|u+v|2 = (u+v)T(u+v) = (uT+vT)(u+v) = uTu+uTv+vTu+vTv = 1+0+0+1 = 2,

so the length of vector u + v is 2.

Similarly,

|uv|2 = (uv)T(uv) = (uTvT)(uv) = uTuuTvvTu+vTv = 100+1 = 2,

so the length of vector u v is 2.

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2020-03-20 00:00
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