Exercise 1.6.18

Answers

Assume A = [ab c d ], and take Ax1 = λ1x1 and Ax2 = λ2x2 for the two eigenvectors, solve for the a,b,c,d, we see that a = d, b = c, so A = [ab b a ]

User profile picture
2020-03-20 00:00
Comments