Exercise 1.6.22

Answers

A has eigenvalues of λ1 = 1 and λ2 = 3, with corresponding eigenvectors v1 = [1 1 ] and v2 = [ 1 1 ]. So we have

A = X1 = [1 1 1 1 ] [10 0 3 ] [1 2 1 2 1 21 2 ]

Ak = [1 1 1 1 ] [1 0 0 3k ] [ 1 2 1 2 1 21 2 ] = 1 2 [ 1 + 3k1 3k 1 3k1 + 3k ]

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2020-03-20 00:00
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