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Linear Algebra and Learning from Data

Exercise 1.6.24

Answers

$AB = X Λ_{1} X^{- 1} X Λ_{2} X^{- 1} = X Λ_{1} Λ_{2} X^{- 1}$
$BA = X Λ_{2} X^{- 1} X Λ_{1} X^{- 1} = X Λ_{1} Λ_{2} X^{- 1}$

So $AB = BA$ .

niuers

2020-03-20 00:00

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