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Exercise 1.7.15

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$D_{1}$ = 2
$D_{2}$ = 6
$D_{3}$ = 30

So the first pivot is 2, the second pivot is $\frac{D_{2}}{D_{1}} = 3$ and the third pivot is $\frac{D_{3}}{D_{2}} = 5$ . This agrees with pivots computed from elimination.

niuers

2020-03-20 00:00

Exercise 1.7.15

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