Exercise 1.7.5

Answers

  • S has eigenvalues of λ1 = 4 and λ2 = 2, with corresponding eigenvectors x1 = 1 2 [ 1 1 ] and x2 = 1 2 [ 1 1 ]. So we have

    S = QT = λ 1x1x1T+λ 2x2x 2T = 2 [11 1 1 ]+ [ 1 1 1 1 ]
  • B has eigenvalues of λ1 = 0 and λ2 = 25, with corresponding eigenvectors x1 = 1 5 [ 4 3 ] and x2 = 1 5 [ 3 4 ]. So we have

    B = QT = λ 1x1x1T+λ 2x2x 2T = [ 9 12 12 16 ]
User profile picture
2020-03-20 00:00
Comments