Exercise 1.8.11

Answers

The trace of S is 0. By equation (21), its eigenvalues are in pairs of σk and σk, so the sum of eigenvalues are also 0.

If A is a square diagonal matrix with entries 1,2,,n, then its eigenvalues are 1,2,,n. Since its real, symmetric matrix, Both its right and left singular vectors are xi = [0 0 1 0 ], where 1 appears in the ith position for the ith eigenvalue.

The 2n eigenvalues of S are: 1,2,,n,1,2,,n.

The 2n eigenvectors of S are: si = [0 0 1 0 0 0 1 0 ] and sj = [ 0 0 1 0 0 0 1 0 ]

Where i,j = 1,2,,n

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2020-03-20 00:00
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