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Exercise 2.2.14

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$e = b - p = (- 1, 3, - 5, 3)$ , it is perpendicular to both columns of the same matrix $A$ . Because $e^{T} a_{1} = - 1 + 3 - 5 + 3 = 0$ , and $e^{T} a_{2} = 0 + 3 - 15 + 12 = 0$ . Since $e$ is perpendicular to both columns of the same matrix $A$ , it is perpendicular to the column space of $A$ , the shortest distance from $b$ to the column space of $A$ is $| e | = \sqrt{1 + 9 + 25 + 9} = \sqrt{44}$ .

niuers

2020-03-20 00:00

Exercise 2.2.14

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