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Exercise 2.3.1

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$| A^{T} A | = | V Σ^{2} V^{T} | = | Σ^{2} | = σ_{1}^{2}$ , $| {(A^{T} A)}^{- 1} | = | V Σ^{- 2} V^{T} | = | Σ^{- 2} | = σ_{r}^{- 2}$ , so we have $| A^{T} A | | {(A^{T} A)}^{- 1} | = \frac{σ_{1}^{2}}{σ_{r}^{2}}$ , it’s the square of $| A | | A^{- 1} | = \frac{σ_{1}}{σ_{r}}$ .

niuers

2020-03-20 00:00

Exercise 2.3.1

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