Exercise 2.3.6

Answers

Since $A v_{i} = σ_{i} u_{i}$ , so $A v_{i}$ is in the column space of $A$ , so $u_{i}$ is in the column space of $A$ .

Let $A = U Σ V^{T}$ , we can derive $Σ V = A^{T} U$ , so $v_i = 1 $σ_{i}$ A^Tu_i$,it′sclearthat $v i$ isintherowspaceof $A$ .

niuers

2020-03-20 00:00