Exercise 2.3.9

Answers

If we set 𝜖 = 0, and from problem 8, we see the two orthogonal vectors are approximately q1 = 1 3 [ 1 1 1 ], q2 = 3 2 [ 2 3 1 3 1 3 ]

and r1 = [33 1 3 ] and r2 = [002 3 ]

So we have A = QR+O(𝜖) = [ 1 3 2 6 1 3 1 6 1 3 1 6 ] [ 33 1 3 0 0 2 3 ] +O(𝜖) = [111 1 1 0 110 ]+ [000 0 𝜖 0 000 ]

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2020-03-20 00:00
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