Exercise 3.2.2

Answers

Let A = S + uuT and B = A + vvT, also, let the eigenvalues of A be z1 z2 zn.

So we have z1 λ1 z2 zn λn. We also have

α1 z1 α2 z2 αn zn.

For 2 i n, we have αi1 zi1 λi1 zi αi+1, so in the end we have

α1 λ1 α3 λ3 α5 λn2 αn λn and α2 λ2 α4 λ4 α6 λn2 αn λn

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2020-03-20 00:00
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