Exercise 3.2.2

Answers

Let A = S + uuT and B = A + vvT, also, let the eigenvalues of A be z1 ≥ z2 ≥⋯ ≥ zn.

So we have z1 ≥ λ1 ≥ z2 ≥⋯ ≥ zn ≥ λn. We also have

α1 ≥ z1 ≥ α2 ≥ z2 ≥⋯ ≥ αn ≥ zn.

For 2 ≤ i ≤ n, we have αi−1 ≥ zi−1 ≥ λi−1 ≥ zi ≥ αi+1, so in the end we have

α1 ≥ λ1 ≥ α3 ≥ λ3 ≥ α5 ≥…λn−2 ≥ αn ≥ λn and α2 ≥ λ2 ≥ α4 ≥ λ4 ≥ α6 ≥…λn−2 ≥ αn ≥ λn

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2020-03-20 00:00
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