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Exercise 3.2.9
Answers
We have , so is diagonal and thus symmetric, is lower triangular matrix, which is invertible, so we see that is a congruent matrix to . Apply the “Law of Inertia”, we can say that and have the same number of positive/negative/zero eigenvalues. On the other side, we know that the eigenvalues of are actually the elements on its diagonal, i.e. the pivots of .
So we conclude that the signs of the pivots of (in ) match the signs of the eigenvalues of .