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Exercise 3.3.6

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If $X$ is invertible, and $AX - XB = C$ , we have $AXX X^{- 1} - X^{- 1} XXB = A^{'} X^{- 1} - X^{- 1} B^{'} = C$ Since $X$ is invertible, we have ${¯AXX}^TAXX = {¯X}^T{¯X}T{¯A}AXX = $

niuers

2020-03-20 00:00

Exercise 3.3.6

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