Exercise 3.4.3

Answers

We have Lagrangian as L(x,y) = λx1 + y(xTw 1) where w = (2,3), assume x = (x1,x2), we have L(x,y) = λ(|x1| + |x2|) + y(2x1 + 3x2 1). Take derivatives of L(x,y) w.r.t. x1,x2,y, we have

  • ∂L x1 = λx1 + 2y = 0 when x1 > 0
  • ∂L x2 = λx2 + 3y = 0 when x2 > 0
  • ∂L ∂y = 2x1 + 3x2 1 = 0

Solve the equations we find x1 = 2 13,x2 = 3 13

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2020-03-20 00:00
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