Exercise 4.1.7

Answers

Since ππ cos (nx)dx = 0 for any n, and ππ cos (nx)cos (mx)dx = 0, when nm, we have

  • 2πa0 = ππf(x)dx = π, we have a0 = 1 2
  • ππ cos (x)f(x)dx = π2π2 cos (x)dx = 2, ππa1 cos 2(x)dx = a1π, so a1 = π 2
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2020-03-20 00:00
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