Exercise 4.5.4

Answers

(ei𝜃 + 1)(ei𝜃 + 1) = 1 ei𝜃 ei𝜃 + 1 = ei𝜃 + 2 ei𝜃

We see that in the limit a1 = a1 = 1

This agrees with the LU in the limit, that is (1)(1) + (1)(1) = 2

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2020-03-20 00:00
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