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Exercise 4.5.5

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Suppose in the last column of $A$ , we have $A_{n - 1, n} = a, A_{n, n} = b$ , so with $A^{T} A = S$ , we have $a^{2} + b^{2} = 5$ , and $ab = - 2$ , solve the equations we have $(a, b) = (- 2, 1), (2, - 1), (1, - 2), (- 1, 2)$

Since $5 - 2 e^{i𝜃} - 2 e^{- i𝜃} = (- e^{i𝜃} + 2) (- e^{- i𝜃} + 2)$ , the diagonal term should be 2, so we have $a = - 1, b = 2$

niuers

2020-03-20 00:00

Exercise 4.5.5

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