Exercise 5.1.13

Answers

2πp(x)dxp(y)dy = 2πp(x)p(y)dxdy = 2π 1 2πex2 2 1 2πey2 2 dxdy =ex2+y2 2 dxdy =02π0er2 2 rdrd𝜃 = 02πer2 2 |0d𝜃 = 2π
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2020-03-20 00:00
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