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Exercise 5.1.8

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$σ^{2} = \sum p_{i} {(x_{i} - m)}^{2} = \sum p_{i} (x_{i}^{2} - 2 m x_{i} + m^{2}) = \sum p_{i} x_{i}^{2} - 2 m \sum p_{i} x_{i} + m^{2} \sum_{p} i = \sum p_{i} x_{i}^{2} - 2 m^{2} + m^{2} = \sum p_{i} x_{i}^{2} - m^{2}$

niuers

2020-03-20 00:00

Exercise 5.1.8

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