Homepage › Solution manuals › Gilbert Strang › Linear Algebra and Learning from Data › Exercise 5.3.2

Exercise 5.3.2

Answers

$K_{X + Y} (t) = \log E [e^{t (X + Y)}] = \log E [e^{tX} e^{tY}] = \log E [e^{tX}] E [e^{tY}] = \log E [e^{tX}] + \log E [e^{tY}] = K_{X} (t) + K_{Y} (t)$

niuers

2020-03-20 00:00

Exercise 5.3.2

Answers

Comments

Add answer