Exercise 5.4.8

Answers

$p (x_{1}) = p_{11} + p_{12} = 0.1 + 0.3 = 0.4$

$p (y_{2} | x_{1}) = \frac{p (y_{2}, x_{1})}{p (x_{1})} = \frac{p_{12}}{p_{1}} = \frac{0.3}{0.4} = 0.75$

niuers

2020-03-20 00:00