Exercise 5.5.3

Answers

  • p(x,y)dxdy =p(x)p(y)dxdy =xp(x)dxyp(y)dy =xp(x)dx = 1
  • $ (x+y)p(x,y)dxdy =(x+y)p(x)p(y)dxdy =_xxp(x)_yp(y)dydx+_yyp(y)_xp(x)dxdy =_xxp(x)dx+_yyp(y)dy = m_1+m_2$.
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2020-03-20 00:00
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