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Exercise 6.1.15

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$f (\frac{3}{4} x + \frac{1}{4} y) = f (\frac{1}{2} x + \frac{1}{2} (\frac{1}{2} x + \frac{1}{2} y)) \leq \frac{1}{2} f (x) + \frac{1}{2} f (\frac{1}{2} x + \frac{1}{2} y) \leq \frac{1}{2} f (x) + \frac{1}{2} (\frac{1}{2} f (x) + \frac{1}{2} f (y)) = \frac{3}{4} f (x) + \frac{1}{4} f (y)$

niuers

2020-03-20 00:00

Exercise 6.1.15

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