Exercise 6.2.2

Answers

L(x,λ) = 1 2(x12 + 4x 22) + λ(2x 1 + x2 5), taking derivatives w.r.t. x1,x2,λ, we have

  • ∂L x1 = x1 + 2λ = 0
  • ∂L x2 = 4x2 + λ = 0
  • ∂L ∂λ = 2x1 + x2 5 = 0

Solve the equations we have x1 = 40 17,x2 = 5 17,λ = 20 17

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2020-03-20 00:00
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