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Linear Algebra and Learning from Data

Exercise 7.3.6

Answers

Through computational graph, if we let $s = x^{3}$ , $c = x - y$ , then $F = sc$ , so we have $s = 8, c = - 1$

$\frac{∂F}{∂x} = \frac{∂F}{∂s} \frac{∂s}{∂x} + \frac{∂F}{∂c} \frac{∂c}{∂x} = c (3 x^{2}) + s \times 1 = (- 1) \times (3 \times 2^{2}) + 8 \times 1 = - 4$
$\frac{∂F}{∂y} = \frac{∂F}{∂s} \frac{∂s}{∂y} + \frac{∂F}{∂c} \frac{∂c}{∂y} = s \times (- 1) = - 8$

niuers

2020-03-20 00:00

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