Exercise 1.2.17 (Consecutive numbers)

Question

Evaluate $(n,n+1)$ and $[n,n+1]$ where $n$ is a positive integer.

Richard Ganaye · Accepted Answer

\begin{proof} Since $(n+1) - n = 1$, 
$$n \wedge (n+1) = 1.$$
Then Theorem 1.13, applied to $n>0, n+1>0$ shows that
$$n \vee (n+1) = n(n+1).$$
\end{proof}

Exercise 1.2.17 (Consecutive numbers)

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Exercise 1.2.17 (Consecutive numbers)

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