Exercise 1.2.4 (Least common multiple)

Question

Find the least common multiple (l.c.m.) of (a) $482$ and $1687$, (b) $60$ and $61$.

Richard Ganaye · Accepted Answer

\begin{proof} 
\begin{enumerate}
\item[(a)] Since $\mathrm{gcd}(482,1687) = 241$, we obtain (Theorem 1.13)
$$\mathrm{lcm}(482,1687) = \frac{482 	imes 1687}{241} = 3374.$$
\item[(b)] Here $\mathrm{gcd}(60,61) =1$, so
$$\mathrm{lcm}(60,61) = 60 	imes 61 = 3660.$$
\end{enumerate}
\end{proof}

Exercise 1.2.4 (Least common multiple)

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Exercise 1.2.4 (Least common multiple)

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