Exercise 1.3.9 (Any prime of the form $3k+1$ is of the form $6k+1$)

Question

Prove that any prime of the form $3k+1$ is of the form $6k+1$.

Richard Ganaye · Accepted Answer

\begin{proof} Let $p = 3k +1$ a prime number. Then $p 
e 2$, thus $p$ is odd. Therefore $3k$ is even, thus $k = 2K$ is even. This gives $p = 6K + 1$ for some integer $K$.
\end{proof}

Exercise 1.3.9 (Any prime of the form $3k+1$ is of the form $6k+1$)

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Exercise 1.3.9 (Any prime of the form $3k+1$ is of the form $6k+1$)

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