Exercise 2.2.13 (Example of Problem 12)

Solve 3 x 1 ( mod 125 ) by Problem 12, taking x 1 = 2 .

Answers

Proof. By Exercise 12, the solution of 3 x 1 ( mod 5 3 ) is x s the nearest integer to y s = ( 1 a x 1 ) s a .

Here x 1 = 2 , a = 3 , s = 3 , thus

y s = 1 3 ( 1 3 × 2 ) 3 = 5 3 3 = 125 3 = 42 1 3 .

Therefore the solution of 3 x 1 ( mod 125 ) is x s = 42 .

Check: 3 × 42 = 126 1 ( mod 125 ) . □

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2024-08-09 08:33
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